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0=4.4x^2-4.9x
We move all terms to the left:
0-(4.4x^2-4.9x)=0
We add all the numbers together, and all the variables
-(4.4x^2-4.9x)=0
We get rid of parentheses
-4.4x^2+4.9x=0
a = -4.4; b = 4.9; c = 0;
Δ = b2-4ac
Δ = 4.92-4·(-4.4)·0
Δ = 24.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.9)-\sqrt{24.01}}{2*-4.4}=\frac{-4.9-\sqrt{24.01}}{-8.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.9)+\sqrt{24.01}}{2*-4.4}=\frac{-4.9+\sqrt{24.01}}{-8.8} $
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